(78 n + 42)^2, when n = 91

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21-06-2015
Mathematics

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(78 n + 42)^2, when n = 91

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apologiabiology apologiabiology · Answer 1 · 2015-06-21T22:13:24-04:00

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21-06-2015

so evaluate/subsitue
the equation becomes
(78 times 91+42)^2

pemdas
do what's inside the parenthasees first

start over
parenthasees
exponents
multiplication and division yes 78 times 91
addition and subtraction so

78 times 91 is first
78 times 91=7098
addition
(7098+42)^2
(7140)^2

restart

parentasees simplified
exponents
7140^2=50,979,600

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