Answered

Two equal charges are separated by 6.5 × 10^-11m.

If the magnitude of the electric force between the charges is 9.92 × 10^-4 N, what is the value of q?

Verified Answer :

audreyn06

Answer: 2.16 × 10⁻¹⁷

Explanation:

The formula for Coulomb's law is given by the formula:

\(F = k\dfrac{qQ}{r^{2} }\), where:

  • F is the magnitude of the force between the charges
  • k is Coulomb's constant (8.99 × 10⁹)
  • q and Q are the magnitude of the charges
  • r is the distance between the charges

Since the charges are equal:

\(F = k\dfrac{q^{2} }{r^{2} }\)

We are given:

  • F = 9.92 × 10⁻⁴ N
  • r = 6.5 × 10⁻¹¹ m

Let's plug our given values into the formula:

9.92 × 10⁻⁴ = (8.99 × 10⁹)q²/(6.5 × 10⁻¹¹)²

Solve for q:

4.1912 × 10⁻²⁴ = (8.99 × 10⁹)q²

q² = 4.662 × 10⁻³⁴

q = 2.16 × 10⁻¹⁷

The value of q is 2.16 × 10⁻¹⁷ C.

Related Questions