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What is the diameter of a hemisphere with a volume of 8514 cm³, to the nearest tent

Verified Answer :

To determine the diameter of a hemisphere given its volume, we can follow these steps:

1. Understand the relationship between volume and radius for a hemisphere:
The formula for the volume of a hemisphere is:
\(\[ V = \frac{2}{3} \pi r^3 \]\)
where \(\( V \)\) is the volume and \(\( r \)\) is the radius of the hemisphere.

2. Solving for the radius \(\( r \)\):
Rearrange the formula to solve for the radius:
\(\[ r^3 = \frac{3}{2} \frac{V}{\pi} \]\)
Taking the cube root of both sides gives:
\(\[ r = \left( \frac{3}{2} \frac{V}{\pi} \right)^{\frac{1}{3}} \]\)

3. Insert the given volume:
Plug in the given volume \(\( V = 8514 \text{ cm}^3 \)\):
\(\[ r = \left( \frac{3}{2} \frac{8514}{\pi} \right)^{\frac{1}{3}} \]\)

4. Calculate the radius:
After performing the calculation, we get:
\(\[ r \approx 15.96 \text{ cm} \]\)

5. Determine the diameter of the sphere:
Since the diameter \(\( D \)\) of a sphere is twice the radius, we calculate it as:
\(\[ D = 2r \approx 2 \times 15.96 = 31.92 \text{ cm} \]\)

6. Round the diameter to the nearest tenth:
Rounding 31.92 to the nearest tenth, we get:
\(\[ D \approx 31.9 \text{ cm} \]\)

Thus, the diameter of the hemisphere, to the nearest tenth of a centimeter, is approximately 31.9 cm.