Answer:
Volume: \(0.24\; {\rm m^{3}}\).
Density: \(40\; {\rm kg\cdot m^{-3}}\).
Explanation:
This question models the sheet of the foam as a rectangular prism. The volume of a rectangular prism is the product of the length of its sides:
\(V = (3\; {\rm m}) \times (1\; {\rm m}) \times (0.08\; {\rm m}) = 0.24\; {\rm m^{3}}\).
To find the average density of the foam, divide the mass of the foam by volume. Assuming that the mass measure \(m = 9.6\; {\rm kg}\) accounts for the effect of buoyancy on the foam. Average density of the foam would be:
\(\displaystyle \rho = \frac{m}{V} = \frac{9.6\; {\rm kg}}{0.24\; {\rm m^{3}}} = 40\; {\rm kg\cdot m^{-3}}\).
