A town has a population of 5000 and grows at 3.5% every year. What will be the population after 15 years, to the nearest whole number?
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Verified Answer :

To determine the population of a town after a certain number of years given an initial population and a constant growth rate, we can use the formula for exponential population growth. The formula is:

\(\[ P(t) = P_0 \times (1 + r)^t \]\)

Where:
- \(\( P(t) \)\) is the population after \(\( t \)\) years.
- \(\( P_0 \)\) is the initial population.
- \(\( r \)\) is the growth rate per period (expressed as a decimal).
- \(\( t \)\) is the number of periods (years in this case).

Given the parameters:
- Initial population, \(\( P_0 = 5000 \)\)
- Growth rate, \(\( r = 0.035 \)\) (which is 3.5% as a decimal)
- Number of years, \(\( t = 15 \)\)

We substitute these values into the formula:

\(\[ P(15) = 5000 \times (1 + 0.035)^{15} \]\)

First, calculate the growth factor:

\(\[ 1 + 0.035 = 1.035 \]\)

Next, raise this growth factor to the power of 15:

\(\[ 1.035^{15} \approx 1.668 \]\)

Now, multiply this result by the initial population:

\(\[ P(15) = 5000 \times 1.668 \approx 8340 \]\)

The population after 15 years, rounded to the nearest whole number, is:

\(\[ \boxed{8340} \]\)