To find the current that a DC motor "draws" when operating at full load (full power output), we can use the power equation for DC circuits. The formula that relates power, voltage, and current is given by:
\(\[ P = V \times I \]\)
Where:
- \(\( P \)\) is the power (in watts, W)
- \(\( V \)\) is the voltage (in volts, V)
- \(\( I \)\) is the current (in amperes, A)
Here are the steps to solve for the current:
1. Identify the given values:
- Power (\(\( P \)\)) is given as 1.50 kilowatts (kW)
- Operating voltage (\(\( V \)\)) is given as 300 volts (V)
2. Convert the power from kilowatts to watts:
\(\[ 1.50 \, \text{kW} = 1.50 \times 1000 \, \text{W} = 1500 \, \text{W} \]\)
3. Rearrange the power equation to solve for current (\(\( I \)\)):
\(\[ I = \frac{P}{V} \]\)
4. Substitute the known values into the equation:
\(\[ I = \frac{1500 \, \text{W}}{300 \, \text{V}} \]\)
5. Perform the division to find the current:
\(\[ I = \frac{1500}{300} \, \text{A} = 5 \, \text{A} \]\)
So, the current drawn by the motor when operating at full load (full power output) is \(\( 5 \)\) amperes (A).
