Answer:
\(23.1\; {\rm J}\). (\(\text{$\texttt{2}$, $\texttt{3}$, and $\texttt{1}$}\).)
Explanation:
The work that a force exerted on an object is equal the product of:
- the force, and
- the displacement of the object in the direction of the force.
In this question, assuming that the object is moving in the same direction as the external \(35.0\; {\rm N}\) force (horizontal.) The displacement in the direction of this force would be \(60.9\; {\rm cm}\) as given.
The question is asking for a result measured in joules. Note that \(1\; {\rm J} = 1\; {\rm N\cdot m}\). While the force is already measured in the standard unit of newtons, make sure the displacement of the object is also in the appropriate unit, meters:
\(\displaystyle 60.9\; {\rm cm} \times \frac{1\; {\rm m}}{100\; {\rm cm}} = 0.609\; {\rm m}\).
Hence, the work that this force exerted on the object would be:
\(\begin{aligned}(\text{work}) &= (\text{force})\, (\text{displacement}) \\ &= (0.609\; {\rm m})\, (35.0\; {\rm N}) \\ &\approx 21.3\; {\rm N\cdot m} \\ &= 21.3\; {\rm J}\end{aligned}\).
(Rounded to three significant figures.)
