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A 5.0-kilogram sphere, starting from rest, falls freely 22 meters in 3.0 seconds near the surface of a planet.

Compared to the acceleration due to gravity near Earth’s surface, the acceleration due to gravity near the

surface of the planet is approximately

(1) the same (3) one-half as great

(2) twice as great (4) four times as great

Verified Answer :

Giovi

(3) one-half as great;
Consider the relationship:
\(y_{f}-y_{i}=v_{i}t+ \frac{1}{2} at^{2}\)
with your data you get:
\(-22=0+ \frac{1}{2}a*9\)
\(a=-4.88m/s^{2}\)
approx one-half of \(g=-9.8m/s^{2}\)

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