Answer:
2 distinct zeroes
Step-by-step explanation:
It would be better to completely factor the equation, so factor x^2 -2x -15. Which is (x-5)(x+3)
so p(x) = (x+3)(x-5)(x+3)
Now since p(x) = 0 when x = -3, and 5. there are 2 distinct zeroes in this function. Hope that answers your question.
If p(x) was (x+3)(x-5)(x-3), it would be 3 because y = 0 when x = -3, 5, 3
