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A string with a length of 0.85 m is fixed at both ends. The string is plucked so that there are 4

nodes along

the string, in addition to those at either end.

AWhat is the wavelength of the interfering waves for this mode?

Verified Answer :

durojaiyesamuel519

Answer:

The wavelength of the interfering waves for this mode is 0.425 meters.

Explanation:

To find the wavelength \( \lambda \) of the interfering waves for this mode, we can use the formula:

\[ \lambda = \frac{2L}{n} \]

Where:

- \( \lambda \) is the wavelength,

- \( L \) is the length of the string (0.85 m in this case),

- \( n \) is the number of nodes along the string (in this case, 4 nodes in addition to those at either end).

Substituting the given values into the formula:

\[ \lambda = \frac{2 \times 0.85}{4} \]

\[ \lambda = \frac{1.7}{4} \]

\[ \lambda = 0.425 \, \text{m} \]

So, the wavelength of the interfering waves for this mode is 0.425 meters.

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