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In a class of 30 students, 12 have a brother and 5 have a sister. There are 15 students who do not
have any siblings. What is the probability that a student chosen randomly from the class is an
only child?
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Verified Answer :

GinnyAnswer

Let's solve the problem step-by-step.

1. We are given the total number of students in the class, which is 30.

2. We are also told the number of students who do not have any siblings, which is 15.

Now, we are interested in finding the probability that a student, chosen at random from the class, is an only child.

The probability (P) of an event is calculated using the formula:

P(event) = Number of favorable outcomes / Total number of outcomes

In this scenario:

- The number of favorable outcomes is the number of students who are only children, which we are given as 15.
- The total number of outcomes is the total number of students in the class, which is 30.

So using the probability formula, we calculate the probability that a student chosen at random is an only child:

P(only child) = Number of students without siblings / Total number of students
= 15 / 30

When we simplify 15/30, we get:

P(only child) = 0.5

Therefore, the probability that a randomly chosen student from the class is an only child is 0.5 or 50%.

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