Answer : v = 69 m/s.
Explanation :
It is given that,
The momentum of a bald eagle in flight, \(p = 345\ Kgm/s\)
Mass of the eagle, m = 5 kg
We know that the momentum of any object is defined as the product of mass and the velocity with which it is moving.
\(p=mv\)
\(v=\dfrac{p}{m}\)
\(v=\dfrac{345\ kgm/s}{5\ kg}\)
\(v=69\ m/s\)
The velocity of the eagle is 69 m/s.
Hence, this is the required solution.
