Answer : The number of moles of \(NO_3\) is, 0.1 moles
Solution : Given,
Mass of \(NO_3\) = 6.2 g
Molar mass of \(NO_3\) = 62 g/mole
Now we have to calculate the moles of \(NO_3\).
\(\text{Moles of }NO_3=\frac{\text{Mass of }NO_3}{\text{Molar mass of }NO_3}=\frac{6.2g}{62g/mole}=0.1moles\)
Therefore, the number of moles of \(NO_3\) present in 6.2 g is, 0.1 moles