For this case we have the following quadratic equation:
\(2x ^ 2 = 4x - 7\)
Rewriting the equation we have:
\(2x ^ 2 - 4x + 7 = 0\)
From here, we have:
\(a=2 b = -4c = 7\)
Substituting values in the quadratic equation we have:
\(x = \frac{-b+/-\sqrt{b^2-4ac}}{2a}\)
\(x = \frac{-(-4)+/-\sqrt{(-4)^2-4(2)(7)}}{2(2)}\)
Rewriting the equation we have:
\(x = \frac{4+/-\sqrt{16-56}}{4}\)
\(x = \frac{4+/-\sqrt{-40}}{4}\)
\(x = \frac{4+/-\sqrt{-4*10}}{4}\)
\(x = \frac{4+/-2i\sqrt{*10}}{4}\)
\(x = \frac{2+/-i\sqrt{*10}}{2}\)
Answer:
The values of x are given by:
\(x = \frac{2+i\sqrt{*10}}{2}\)
\(x = \frac{2-i\sqrt{*10}}{2}\)
