Verified Answer :

Since3122015

\(4x^2-12x=7\\4x^2-12x-7=0\\x=\frac{-b+-\sqrt{b^2-4ac}}{2a}\\x=\frac{-(-12)+-\sqrt{(-12)^2-4(4)(-7)}}{2(4)}\\x=\frac{12+-\sqrt{144+112}}{8}\\x=\frac{12+-\sqrt{256}}{8}\\x=\frac{12+-16}{8}\\x=\frac{-4,28}{8}\\x=\frac{-1}{2},\frac{7}{2}\)

x = -0.5, 3.5

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