we have that
\(AB=34\)
sin ∠ABC=\(\frac{8}{17}\)
we know that
in the right triangle ABC
sin ∠ABC is equal to \(\frac{AC}{AB}\)
AC is the opposite side angle B
AB is the Hypotenuse
sin ∠ABC=\(\frac{8}{17}\) equation 1
sin ∠ABC=\(\frac{AC}{34}\) equation 2
equate equation 1 and equation 2
\(\frac{8}{17} = \frac{AC}{34} \\ \\ AC=34* \frac{8}{17} \\ \\ AC=16\)
the answer is
\(AC=16\)