If you have:
\(log_{2}(8)+log_{9}(2)=\)
I would change base into the second log as:
\(log_{2}(8)+ \frac{ log_{2}(2)}{ log_{2}(9)}=\)
Solving the logs I get:
\(3+ \frac{1}{3} = \frac{10}{3}\)
I used an approx value for the \(log_{2}(9)\) using \(log_{2}(9)=3\) (it is a little bit more than 3).
