Answer:
To obtained the smallest number multiply the number with \((10)^{-1}\).
Step-by-step explanation:
Given : \((10)^{-1},\ (10)^0,\ (10)^1,\ (10)^2\)
We have to find when we multiply any number with the given number which number will give the smallest value.
Consider the given numbers,
\((10)^{-1},\ (10)^0,\ (10)^1,\ (10)^2\)
We find the values of each number one by one,
1) consider \((10)^{-1}\), using property of exponents \(a^{-m}=\frac{1}{a^m}\), we have
\((10)^{-1}=\frac{1}{10}=0.1\)
2) \((10)^0\) we know any thing to power 0 is always 1.
\((10)^0=1\)
3) \((10)^1\) is same as itself that is 10.
4) \((10)^2\) is \((10)\times 10=100\)
Thus, To obtained the smallest number multiply the number with \((10)^{-1}\).
