How do i solve x/2+1/3=x/3+1/2
x/2+1/3=x/3+1/2x/2=x/3+1/2-1/3x/2 - x/3 = 3/6 - 2/6x/2 - x/3 = 1/63x/6 - 2x/6 = 1/6x/6 = 1/6x = 1/6 * 6x = 1
\(\frac{1}{2}x + \frac{1}{3} = \frac{1}{3}x + \frac{1}{2} \\\frac{1}{6}x + \frac{1}{3} = \frac{1}{2} \\\frac{1}{6}x = \frac{1}{6} \\6(\frac{1}{6}x) = 6(\frac{1}{6}) \\x = 1\)
