Use the distance formula to find the distance between two points.
For any points \(P(x_1,\ y_1)\) and \(Q(x_2,\ y_2)\), the distance between them \(PQ=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\)
\(EA=\sqrt{(3-5)^2+(1-1)^2}=\sqrt{(-2)^2+0^2}=\sqrt{4}=2\)
\(EB=\sqrt{(3-2)^2+(1-4)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}\)
\(EC=\sqrt{(3-3)^2+(1-7)^2}=\sqrt{0^2+(-6)^2}=\sqrt{36}=6\)
\(ED=\sqrt{(3-7)^2+(1-2)^2}=\sqrt{(-4)^2+(-1)^2}=\sqrt{16+1}=\sqrt{17}\)
The correct answer is C(3, 7).
(you don't even need to use the distance formula to realize this since it's 6 units directly above E(3, 1))
