Write the equation of a line with a slope of 4 and a y-intercept of −3. 4x + y = −3 4x – y = −3 y = −3x + 4 y = 4x − 3
Knowing the slope and y-intercept of a line you can put its equation in slope-intercept form.
The slope-intercept form equation of a line is \(y=mx+b\) where \(m\) is the slope and \(b\) is the y-intercept.
In this case, since the slope is 4 and the y-int. is -3, our equation must be
\(\boxed{y=4x-3}\)
y=4x-3
4 is the slope and -3 is the y intercept
By plugging these values into the slope intercept form: y=mx+b I came up with the previous answer-y=4x-3
m= the slope, and b=the y intercept