Using newton's second law of motion, if the force on an object is 20n, and its mass is 5g, what is the acceleration? Can someone explain to me in a simple way how to do this? I have tried but the formulas I see are confusing. Thank you :)
Do 20 divided by 5 and you'll get 4! All you have to do is take the net force (20n) and divide it by the mass (5g) and you'll have the answer! :)
Answer: The acceleration of the object will be 4000 \(m/s^2\)
Explanation:
According to second law of motion:
\(Force(F)=mass(m)\times acceleration(a)\)
Unit of the force: \(N=kg\times m/s^2\)
According to question we have :
Force = 20 N
Mass of the object = 5 g = 0.005 kg (1 kg =1000 g)
Acceleration = ?
By using the second law of motion = F= ma
\(20 N= 0.005 kg\times a\)
\(a=\frac{Force}{mass}=\frac{20 N}{0.005 kg}=4000 m/s^2\)
The acceleration of the object will be 4000 \(m/s^2\)