RaisaMindell204
Answered

What is the total energy released when

9.11 × 10^−31 kilogram of mass is converted into

energy?

(1) 2.73 × 10^−22 J (3) 9.11 × 10^−31 J

(2) 8.20 × 10^−14 J (4) 1.01 × 10^−47 J

Verified Answer :

Giovi

I found (2).
Using \(E=m c^{2} =9.11* 10^{-31}* (3*10^{8} )^{2} =8.2* 10^{-14}J\)

Answer:

The correct answer is option 2,

The total energy released is \(8.20 * 10^{-14} J\\\)

Explanation:

As per Einstein theory of relativity,

\(E = mc^2\\\)

where

"E" is the energy produced by mass conversion

"m" is the mass converted

"c" speed of light

Substituting the given values in above equation we get -

\(E = (9.11 * 10^{-31}) Kg * ( 3 * 10^{8} \frac{m}{s} )^2\\= 8.20 * 10^{-14} J\\\)

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