A sample of an unknown substance has a mass of 89.5 g. If 345.2 J of heat are required to heat the substance from 285 K to 305 K, what is the specific heat of the substance?
The specific heat is the heat needed per unit mass to raise the temperature by 1 degree celsius. So the specific heat = heat/(massΔT) = 345.2/[89.5(305-285)]=0.193 J/(g*℃). When using ΔT, the unit K and ℃ are the same.
The specific heat of the unknown sample has been \(\rm \bold{0.192\;\;J/g^\circ C}\).
Specific heat has been defined as the amount of heat required to raise the temperature of 1 gram of substance by 1 degree Celsius.
The specific heat (c) for a substance can be given by:
\(Q=mc\Delta T\) ......(i)
Where, the heat required by the substance, \(Q=345.2\;\text J\)
The mass of the substance has been, \(m=89.5\;\text g\)
The change in temperature of the system has been, \(\Delta T\)
The change in temperature has been given as:
\(\Delta T=T_f-T_i\)
The initial temperature of the substance, \(T_i=285\;\text K\)
The final temperature of the substance, \(T_f=305\;\text K\)
Substituting the values for the change in temperature, \(\Delta T\):
\(\Delta T=305\;-\;285\;K\\\Delta T=20\;\text K\)
Substituting the values in equation (i):
\(345.2=89.5\;\times\;c\;\times\;20\\345.2=1,790c\\c=0.192\rm \;J/g^\circ C\)
The specific heat of the unknown sample has been \(\rm \bold{0.192\;\;J/g^\circ C}\).
For more information about specific heat, refer to the link:
https://brainly.com/question/2094845