Answered

What is the period of a sound wave having a

frequency of 340. hertz?

(1) 3.40 × 10^2 s (3) 9.73 × 10^−1 s

(2) 1.02 × 10^0 s (4) 2.94 × 10^−3 s

Verified Answer :

4)2.94 • 10^-3 s

Period=(1/frequency)
Period=(1/340Hz)
Period=.0029411765 s

Answer : The correct option is, (4) \(2.4\times 10^{-3}s\)

Solution :

The relation between the frequency and time period is that the frequency is inversely proportional to the time period.

It is written as,

\(u=\frac{1}{T}\\\\T=\frac{1}{ u}\)

where,

\(u\) = frequency of the sound wave = 340 Hz = \(340s^{-1}\)

T = time period of a sound wave = ?

Now put all the given values in the above expression, we get the time period of the a sound wave.

\(T=\frac{1}{ u}=\frac{1}{340s^{-1}}=2.94\times 10^{-3}s\)

Therefore, the period of a sound wave is, \(2.4\times 10^{-3}s\)

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