Answer:
(4) 90.°
Explanation:
The maximum height reached by the ball depends on the vertical velocity of the ball: the greater the vertical velocity of the ball, the higher the ball will go.
The vertical component of the velocity of the ball is given by:
\(v_y = v_0 sin \theta\)
where
\(v_0 = 10 m/s\) is the initial speed of the ball
\(\theta\) is the angle at which the ball is thrown
Therefore, \(v_y\) will be maximum when \(sin \theta =1\). And by solving this equation, we find that the angle that satisfies this condition is \(\theta=90^{\circ}\), which corresponds to throwing the ball straight up.
