Answer : The volume of 6.00 M HCl needed are, 361.5 ml
Solution :
According to the neutralization law,
\(M_1V_1=M_2V_2\)
where,
\(M_1\) = molarity of HCl solution = 6.00 M
\(V_1\) = volume of HCl solution = ?
\(M_2\) = molarity of another HCl solution = 6.80 M
\(V_2\) = volume of another HCl solution = 319 ml
Now put all the given values in the above law, we get the volume of HCl solution.
\((6.00M)\times V_1=(6.80M)\times (319ml)\)
\(V_1=361.5ml\)
Therefore, the volume of 6.00 M HCl needed are, 361.5 ml
