Kemerer217
Answered

The total amount of electrical energy used by a

315-watt television during 30.0 minutes of

operation is

(1) 5.67 × 10^5 J (3) 1.05 × 10^1 J

(2) 9.45 × 10^3 J (4) 1.75 × 10^1 J

Verified Answer :

naǫ

\(W=Pt\)
W - energy, P - power, t - time

\(P=315 \ W \\ t= 30 \ min= 30 \times 60 \ s = 1800 \ s \\ \\ W=315 \times 1800=567000=5.67 \times 10^5 \ [J]\)

The answer is (1).

skyluke89

The amount of electrical energy used by the television is given by:

\(E=Pt\)

where P is the power of the device and t is the time.


The power of the television is P=315 W, while the total time is

\(t=30.0 min \cdot 60 =1800 s\)

If we substitute these numbers into the formula, we find the energy:

\(E=Pt=(315 W)(1800 s)=5.67 \cdot 10^5 J\)


so, the correct answer is

(1) 5.67 × 10^5 J

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