Let us call p the probability of occurence of the event D: "a student owns a dog"
and q the probability of occurence of the event C: "a student owns a cat"
In this exercice we have to assume that the events D and C are independent which means that none of them influence the occurence of the other. Because if they are not independent there really is noway to deduce q here.
In reality those events would probably not be independent since if I had a dog, I would really think twice before buying a cat ;)
Well if they are independent then you know that The Probability of occurence of D and C at the same time equals P(D)P(C)=pq
So we can deduce that 2/15=1/3q
q=32/15
q=6/15
q=2/5
Once again this is theoritical
