Lascano15
Answered

A 0.50-kilogram puck sliding on a horizontal

shuffleboard court is slowed to rest by a

frictional force of 1.2 newtons. What is the

coefficient of kinetic friction between the puck

and the surface of the shuffleboard court?

(1) 0.24 (3) 0.60

(2) 0.42 (4) 4.1

Verified Answer :

sbcardinals



-The u is what you are trying to find, also known as coefficient of friction.
-Fn is your mass in Newtons, which is 0.5 x 9.8 which equals 4.9
-Fmax is your frictional force. 

When you solve for , your equation becomes

 / Fn = 

 = 1.2N/4.9N

 (coefficient of friction) = 0.25