Solving for systems:
{y=3x+7 & y=5x-7
\(\left\{\begin{array}{ccc}y=3x+7\\y=5x-7\end{array}\right\\\\substitute:\\\\5x-7=3x+7\\5x-3x=7+7\\2x=14\ \ \ \ /:2\\x=7\\\\y=3\cdot7+7=21+7=28\\\\Answer:x=7\ and\ y=28.\)
y = 3x + 7y = 5x-7Now, we know that y = ythus,3x + 7 = 5x-73x - 5x = -7 -7= -2x = -14thus, -x = -14/-2thus, x = 7.Substituting for y,y = 3x + 7= 3 x 7 + 7= 28.Thus, x = 7, y =28