What the center of X^2+(y+3)=9
Assuming you mean \(x^2+(y+3)^2=9\), which is the equation of a circle :the general equation of a circle of radius \(R\) and center \((a,b)\) is \((x-a)^2+(y-b)^2=R^2\) hence here the center is \(\boxed{(0,-3)}\)
