Find the minimum value of 1 + 3(3 −x)²
1 + 3(3 −x)² >= 1, because 3 > 0 and (3 −x)² >=0 => the minimum value of 1 + 3(3 −x)² is 1.
\(for\ every\ x\in R\ is\ (3-x)^2 \geq 0\\\\ (3-x)^2 \geq 0\ \ \ \Rightarrow\ \ 3 (3-x)^2 \geq 0\ \ \ 1+ (3-x)^2 \geq 1\\ \\Ans.\ The\ minimum\ value\ is\ 1\)
