When 50. milliliters of an HNO3 solution is

exactly neutralized by 150 milliliters of a 0.50 M

solution of KOH, what is the concentration of

HNO3?

(1) 1.0 M (3) 3.0 M

(2) 1.5 M (4) 0.5 M

Verified Answer :

The reaction formula is HNO3 + KOH = KNO3 + H2O. The mole number of HNO3 and KOH is the same. So the concentration of HNO3 is 150*0.5/50=1.5 M. So the answer is (2).

Answer : The correct option is, (2) 1.5 M

solution :

According to the neutralization law,

\(M_1V_1=M_2V_2\)

where,

\(M_1\) = molarity of \(HNO_3\) solution = ?

\(V_1\) = volume of \(HNO_3\) solution =  50 ml

\(M_2\) = molarity of KOH solution = 0.50 M

\(V_2\) = volume of KOH solution = 150 ml

Now put all the given values in the above law, we get the volume of \(HNO_3\) solution.

\(M_1\times (50ml)=(0.50M)\times (150ml)\)

\(M_1=1.5M\)

Therefore, the concentration of \(HNO_3\) is, 1.5 M