Anonymous Anonymous

01-06-2015
Physics

Answered

A 0.05-kg car starts from rest at a height of 0.95 m. Assuming no friction, what is the kinetic energy of the car when it reaches the bottom of the hill? (Assume g = 9.81 m/s2.)

Verified Answer :

01-06-2015

Considering conservation of mechanical energy we have:
K+U (start)= K+U (end)
Where:
K=kinetic energy=\(\frac{1}{2}m v^{2}\)
U=potential energy=\(mgh\)
So:
0.050.959.81+0 (start) = 0+K (end)
K (end)=0.5 Joules

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08-11-2020

Answer: What is the answer?

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