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What is the empirical formula for a compound

with the molecular formula C6H12Cl2O2?

(1) CHClO (3) C3H6ClO

(2) CH2ClO (4) C6H12Cl2O2

Verified Answer :

Answer: \(C_3H_6ClO\)

Explanation:

Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.

Thus the compound with molecular formula \(C_6H_{12}Cl_2O_2\) will have simplest ratio of atoms as 3:6:1:1 and thus empirical formula will be \(C_3H_6ClO\).

3. C₃H₆ClO

  • Molecular formulas tell you how many atoms of each element are in a compound, while
  • Empirical formulas tell you the simplest or most reduced ratio of elements in a compound.

Given: Molecular formula=C₆H₁₂Cl₂O₂

So, the simplest or most reduced ratio for this formula is C₃H₆ClO which can be deduced by dividing the molecular formula by 2 in order to get its empirical formula.

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