Solve algebraically 3^x= 243
3^x=243so :³log243=x³log 3^5=xx=5or 5^√243=3
\(3^{x} = 243 \\ln(3^{x}) = ln(243) \\xln(3) = ln(243) \\\frac{xln(3)}{ln(3)} = \frac{ln(243)}{ln(3)} \\x = \frac{ln(243)}{ln(3)} \\x = \frac{ln(3^{5})}{ln(3)} \\x = \frac{5ln(3)}{ln(3)} \\x = 5\)
