The total number of sodium atoms in 46.0 grams of solution is?
molar mass Na = 23g/mol
46g = 456/2 = 2mol
1mol = 6.02210^23 atoms
2mol = 26.02210623
= 1.20410^24 atoms
First step, is to find the Molar Mass.
If you go to the periodic table, the Molar Mass of the Sodium Na is 23g/mol
Second Step, you convert from grams to moles.
number of Mole = mass of sodium / molar mass = \(\frac{46}{23} = 2 mol\)
Third Step, you find the number of atoms.
As We know, Avogadro said that the number of atoms in 1 mole is about \(6.022 * 10^{23}\).
You use the Rule of three and you find the number of atoms!
1 mole = \(6.022 * 10^{23}\) atoms
2 mole = x atomes
x = 2 * ( \(6.022 * 10^{23}\) )
x= \(12.044 * 10^{23}\) atomes
So, there is \(12.044 * 10^{23}\) atoms of Sodium Na in 46g of Solution.
Hope this Helps! :D