what is the mass in grams of 1.5*10^-3 mol of sodium
So n:m/M
m=nxM
Sodium=1.05x10-³x(23.0)
= 2.42x10-²grams
Lead= 1.05x10-³x (207.2)
=2.1756x10-¹ grams
Valium= 0.5x10-³ x (12.0x16 + 1.0x 13 +
12.0 + 126.9 + 14.0 x 2 + 16.0)
=1.94x10-¹ grams
The Formula to find the number of moles is:
Number of Moles = Mass/ Molar Mass
Which means that Mass = Number of Moles * Molar Mass
We know that Number of Moles of Sodium Na = \(1.5*10^_{-3}\) moles
If you check the Periodic Table, Molar Mass of Sodium Na = 23g/mol
So, Mass = \(1.5*10^_{-3} * 23\) = \(3.45 * 10^{-2}\)
So, the mass in grams of \(1.5*10^_{-3}\) mol of Sodium is \(3.45 * 10^{-2}\)
Hope this Helps :)