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In a carnival drawing, a green ticket wins $1, a yellow ticket wins $5, and a blue ticket wins $10. There are 100 green tickets, 25 yellow tickets and 5 blue tickets. In simplest form, what are the odds against winning less than $10?

A1:4
B1:5
C1:10
D1:25

Verified Answer :

Sunnyxo

first, you add up the non-$10 winning cars so 100+25=125.
then you take 5:125 because you want the winning 10$ against not winning. the to get 1 you divide both numbert by 5 to get 1 on the left. so you get 1:25.
hope i helped:)

The odds against winning less than $10 is 1/25 and this can be determined by using the given data.

Given :

  • A green ticket wins $1, a yellow ticket wins $5, and a blue ticket wins $10.
  • 100 green tickets, 25 yellow tickets, and 5 blue tickets.

The following steps can be used in order to determine the odds against winning less than $10:

Step 1 - The total number of green tickets and yellow tickets is 125 (100+25).

Step 2 - Let the odds against winning less than $10 be 'x'.

Step 3 - So, the value of 'x' is calculated as:

\(x = \dfrac{5}{125}\)

\(x = \dfrac{1}{25}\)

Therefore, the correct option is D).

For more information, refer to the link given below:

https://brainly.com/question/795909

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