Verified Answer :

iloveonedirection

\(\frac{3}{8} ... \frac{5}{16}\)

First, find the least common denominator between the two.
Since 8 is a factor of 16, the LCD is 16.

\(\frac{3*2}{8*2}\)

\(\frac{3}{8}= \frac{6}{16}\)

Now, you can compare the numerators.

\(6>5\)

Since 6 is greater than 5, you know that \(\frac{6}{16} > \frac{5}{16}\).

Therefore, we now know that \(\frac{3}{8}\) is larger.

\(\frac{3}{8}=\frac{3\codt2}{8\cdot2}=\frac{6}{16} > \frac{5}{16}\\\\Answer:\frac{3}{8}\ is\ larger\ than\ \frac{5}{16}.\)

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