30-05-2015
Physics

Answered

Determine the potential difference between two charged parallel plates that are 0.50 cm apart and have an electric field strength of 9.0 V/cm.

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chipperrider chipperrider

30-05-2015

\(E = \frac{V}{r} \\ V = \frac{E}{r} \\ V = \frac{9.0V/cm}{0.5cm} \\ V = 18V\)

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30-05-2015

If the field strength between the plates is 9 volts per cm, then over a path of 1/2cm parallel to the field, the potential changes by (1/2) x (9 volts) = 4.5 volts.

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