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12 people are standing in line to buy movie tickets. The theater is running a promotion by giving away 2 concession stand gift cards to the people standing in line.


What is the probability that the 2nd and 3rd people in line will get chosen for the gift cards?

Verified Answer :

IwAsSoMeGuY

1 in 12 chance of second person getting given a ticket
Then a 1 in 11 chance of the third person being given one.
1/12*1/11 = 1/132 chance. However, if it doesn't have to be in order, then there's a 1/12 chance of the third person getting a ticket, then a 1/11 chance of the second person getting one, so another 1/132 chance. Add them together for 2/132, or 1/66 chance

amattimoe

can you clarify, please. do you mean every 2nd and 3rd person?

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