Number A: n
Number B: (n-1)
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Let's search for the value of (n) to find the number A and B...
\(n+\left( n-1 \right) =n+1\\ \\ n+n-1=n+1\\ \\ 2n-1=n+1\\ \\ 2n-n=2\\ \\ n=2\)
If n=2,
Number A = 2
Number B = 1
The two consecutive numbers are 1 and 2.
