\(12-appetizers, \ 9- main\ courses, \ 7\ desserts\\ \\ selection:\ 8\ appetizers,\ 8\ main\ courses, 6\ desserts\\\\a=the\ number\ of\ selection\ of\ appetizers:\\ \\{12 \choose 8}= \frac{12!}{8!\cdot (12-8)!} = \frac{12\cdot11\cdot10\cdot9\cdot8!}{8!\cdot4\cdot3\cdot2} =11\cdot5\cdot9=495\\ \\c=the\ number\ of\ selection\ of\ main\ courses:\\ \\{9 \choose 8}= \frac{9!}{8!\cdot (9-8)!} = \frac{9\cdot8!}{8!\cdot 1} =9\)
\(d=the\ number\ of\ selection\ of\ desserts:\\ \\{7 \choose 6}= \frac{7!}{6!\cdot (7-6)!} = \frac{7\cdot6!}{6!\cdot 1} =7\\ \\the\ number\ of\ selection\ sets\ the\ banquet:\\ \\a\cdot c\cdot d=495\cdot9\cdot7=31185\)
