\(\csc\Theta=\frac{1}{\sin\Theta}\)
Since the function \(\csc\Theta\) is literally defined as the reciprocal of \(\sin\Theta\), any value of \(\Theta\) will satisfy this equation.
A. All real numbers
\(\{\Theta|\Theta\in\mathbb{R}\}\)
Answer:
Option D. All real numbers except multiples of pi
Step-by-step explanation:
It has been given that \(csc(\theta)=\frac{1}{sin\theta }\) and we have to find the domain of the given expression.
As we know \(\frac{1}{sin\theta }\) is defined only when \(sin\theta>0\) or \(sin\theta<0\) but not equal to zero.
Since sine of \(0, \pi, 2\pi......\) are always zero. Therefore domain of \(\frac{1}{sin\theta }\) is \({\theta}<\pi or {\theta}>\pi\)
That means Option D. All real numbers except multiples of pi is the answer.