Verified Answer :

iGreen

We can re-arrange it into slope-intercept form(\(\sf~y=mx+b\)).

\(\sf~y=10-5x\)

Switch -5x and 10 around:

\(\sf~y=-5x+10\)

Now it's in slope intercept form.

\(\sf~y=mx+b\)

Where \(\sf~m\) is the slope, and \(\sf~b\) is the y-intercept.

So in this case, 10 is the y-intercept.

\(\sf~y=-5x+\boxed{\sf10}\)

AL2006

The y-intercept is the point where the graph of the function crosses the y-axis. That's just another way of saying that it's the value of the function when 'x' is zero (because 'x' is zero at every point on the y-axis). / / / When 'x' is zero, y=10-5x is just y=10 , and there's your y-intercept ... y=10.

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