find the roots of this polynomial equation

x^3-2x^2+10x+136=0

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26-05-2015
Mathematics

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find the roots of this polynomial equation

x^3-2x^2+10x+136=0

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Panoyin Panoyin · Answer 1 · 2015-05-26T19:56:53-04:00

x³ - 2x² + 10x + 136 = 0
      x³ - 6x² + 4x² + 34x - 24x + 136 = 0
      x³ - 6x² + 34x + 4x² - 24x + 136 = 0
x(x²) - x(6x) + x(34) + 4(x²) - 4(6x) + 4(34) = 0
   x(x² - 6x + 34) + 4(x² - 6x + 34) = 0
      (x + 4)(x² - 6x + 34) = 0
   x + 4 = 0 U x² - 6x + 34 = 0
      - 4 - 4    x = -(-6) +/- √((-6)² - 4(1)(34))
   x = -4 2(1)
      x = 6 +/- √(36 - 136)
      2
      x = 6 +/- √(-100)
   2
x = 6 +/- 10i
2
      x = 3 + 5i
      x = 3 + 5i U x = 3 - 5i
The solution set is equal to {-4, 3 + 5i}.

find the roots of this polynomial equationx^3-2x^2+10x+136=0

Verified Answer :

Related Questions

find the roots of this polynomial equation

x^3-2x^2+10x+136=0