what is the molarity of a solution of 14.0 g NH4Br in enough H2O to make 150 mL of solution?
The molarity of a solution equals to the mole number of the solute/the volume of the solution. For NH4Br, we know that the mole mass is 98. So the molarity is (14/98) mol /0.15 L=0.95 mol/L.
Explanation:
Molarity is defined as the number of moles per liter of solution.
Mathematically, Molarity = \(\frac{no. of moles}{volume of solution in liter}\)
Since it is given that the molarity of a solution of 14.0 g and volume is 150 mL or 0.15 L.
Whereas number of moles = \(\frac{mass}{molar mass}\)
So, molar mass of \(NH_{4}Br\) is 97.94 g/mol.
Thus, number of moles = \(\frac{14.0 g}{97.94 g/mol}\)
= 0.142 mol
Therefore, calculate the molarity as follows.
Molarity = \(\frac{no. of moles}{volume of solution in liter}\)
= \(\frac{0.142 mole}{0.15 L}\)
= 0.946 mol/L
Hence, we can conclude that molarity of the solution is 0.946 mol/L.