Area of a square with side s is \(\sf{s^2}\)
In your question, the side or s is: \(\sf{8x^7y^3}\)
And so the area of a square with that side length would be:
\(\sf{(8x^7y^3)^2}\)
And using this formula: \(\sf{(a^b)^c =a^{b\times c}}\)
We get that the area is:
\(\sf{(8x^7y^3)^2 = 8^2 x^{7\times 2} y^{3\times 2}}\)
And simplifying that we get the final answer as:
\(\huge{\boxed{\bf{Area=64x^{14}y^{6}}}}\)
